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$(\sin x)^2 - 5\sin x \cos x=0$

What would be the first atep to solve this. I normally get the equation into a quadratic one but I cannot seem to spot the first step here.

What I mean by $(\sin x)^2$ incase there will be confusion is "Sin squared x"

Appreciate any help.

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  • $\begingroup$ But you haven't posted an equation?! $\endgroup$
    – amWhy
    Jan 27 '15 at 18:11
  • $\begingroup$ Welcome to the Math Stack Exchange. We talk of solving equations, but you don't have an equation to solve. Do you mean that $\sin^2 (x) - 5\sin(x) \cos(x) = 0$? $\endgroup$ Jan 27 '15 at 18:11
  • $\begingroup$ Please check the equation - I have added $=0$ - is this what you intended? $\endgroup$
    – Macavity
    Jan 27 '15 at 18:14
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Hint: What you have is $$\sin x \cdot (\sin x - 5\cos x) = 0$$

Now one of the factors must be zero, and when can that happen?

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