# Help With Solving Trigonometric equations

$(\sin x)^2 - 5\sin x \cos x=0$

What would be the first atep to solve this. I normally get the equation into a quadratic one but I cannot seem to spot the first step here.

What I mean by $(\sin x)^2$ incase there will be confusion is "Sin squared x"

Appreciate any help.

• But you haven't posted an equation?! Jan 27 '15 at 18:11
• Welcome to the Math Stack Exchange. We talk of solving equations, but you don't have an equation to solve. Do you mean that $\sin^2 (x) - 5\sin(x) \cos(x) = 0$? Jan 27 '15 at 18:11
• Please check the equation - I have added $=0$ - is this what you intended? Jan 27 '15 at 18:14

Hint: What you have is $$\sin x \cdot (\sin x - 5\cos x) = 0$$