Dedekind Cuts in Construction of the real line [closed]

Is each Dedekind cut a unique real number? or when we apply the process(Dedekind cut), do we get a bunch of real numbers instead of a unique one.

If we get a unique real number, is the unique real number then plotted as a line segment between rationals on the number line? Or is it plotted as a single point (just like 0 and 1)?

If not so, Is the bunch of numbers that we get infinite?

closed as unclear what you're asking by Andrés E. Caicedo, hardmath, dustin, user147263, TravisJan 22 '15 at 3:12

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• Depending on your definition of real number, the answer to the first question may be "Yes, by definition" – Hagen von Eitzen Jan 21 '15 at 10:20
• Lets say it is defined as - a number on the real number line – novice Jan 21 '15 at 10:21
• What is the standard definition btw? – novice Jan 21 '15 at 10:34
• Some authors use Dedekind cuts to represent only non-negative real numbers, so that these sets are known to be bounded below. The negative real numbers can then be represented algebraically. – hardmath Jan 22 '15 at 2:14
• Could you please indicate what is unclear so I may edit the question properly – novice Jan 22 '15 at 8:13

There are several ways to construct (or if you prefer, define) the real numbers. The two most familiar are as Dedekind cuts in $\Bbb Q$, the ordered set of rational numbers, and as equivalence classes of Cauchy sequences of rational numbers with respect to a certain equivalence relation. If one constructs them using Dedekind cuts, then each Dedekind cut is by definition a unique real number. If one constructs them in some other way, it’s no longer the case that each real number is a Dedekind cut in $\Bbb Q$, but it is still true that there is a nice bijection between the set of Dedekind cuts in $\Bbb Q$ and the reals as constructed.
• @novice: No, it's a single point, not a segment. No two rational numbers are adjacent: the average of any two rational numbers is a rational number between them. The gaps in $\Bbb Q$ are a bit more subtle than that. For example, if $R$ is the set of positive rational numbers $x$ such that $x^2>2$, and $L$ is the rest of the rationals, then every member of $L$ is less than each member of $R$, but there is no rational number between $L$ and $R$. In $\Bbb R$ the number $\sqrt 2$ fills that gap. – Brian M. Scott Jan 22 '15 at 2:25