I'm having troubles finding two numbers a,b such that $ 288a+177b=3=gcd(177,288) (1) $

I've been writing the equations of the Euclids algorithm one over another many times to get any pair that verify (1). But, I don't get this yet. I'm trying to solve $ 288x + 177y = 69 $ I understand very well the theorem. But I really, really need help finding the particular solution. If someone can explain me any method, or give me an advice to find a pair (a,b), I would really appreciate it. Thanks for reading,



This is how I do it in my notebook when I have to:

You first have to use the euclidean algorithm to find the greatest common divisor:






$21=(7)3$ Hence the GCD is $3$. the next step is to pass all of the equations except the last so that the small number is alone:






Once I have this I start with the equation $3=45-2(21)$ and I go one by one substituting the smallest factor with the adequate equation and then simplifying:







Suppose $288 a_1 + 177 b_1 = g$ where $\gcd(288, 177)$. The first step in Euclid's algorithm says: you take $288 = 177 + 111$, and $\gcd(288,177) = \gcd(111, 177)$. Corresponding to this, $288 a_1 + 177 b_1 = 111 a_1 + 177 (a_1 + b_1)$, so $111 a_2 + 177 b_2 = \gcd(111,177)$ where $b_2 = a_1 + b_1$. Each step of Euclid's algorithm gives you an equation in the $a$'s and $b$'s. Keep track of these equations. At the end, you'll have one that's easy to solve, and then you work backwards to get $a_1$ and $b_1$.


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