$-\frac76=-\frac {4n}{3}$ struggling on solving this equation I was wondering how to do this equation step by step. I forgot how to but it would be awesome if someone could help me out
$$-\frac76=-\frac {4n}{3}$$
 A: Consider 
$$
\frac{a}{b}=\frac{c}{d}n
$$
where $b,d\neq 0$. Then
$$
n=\frac{ad}{bc}.
$$
Now if you have, 
$$
\frac{a}{b}=\frac{c}{dn}
$$
Then
$$
n=\frac{cb}{da}
$$
Both results were obtained by cross multiplying in order to isolate the unknown variable $n$
A: $$-\frac76=-\frac {4n}{3} $$
$$\frac{-7}{6} \times \frac{-3}4 = \frac{-4n}{3} \times \frac{-3}4$$
$$\frac{21 }{24} = n$$
$$ n = \frac{7}{8} $$
A: $$\frac{-7}{6}=\frac{-4}{3}n\\3\times\frac{-7}{6}=-4\times n\\3\times -7=-4\times6\times n\\\frac{3\times -7}{-4\times 6}=n\\n=\frac{21}{24}=\frac{7}{8}$$
A: It's the same sort of question as "How many dimes are ther in seven nickels?". To answer it, just convert everything to a common denomination--or, in this case, make the fractions being compared have the same denominator.
$$-\frac 76 =-\frac{4n}{3}$$
$$\frac {-7}6 = \frac{-4n}{3}$$
$$\frac {-7}6 = \frac{-4n\cdot 2}{3\cdot 2}$$
$$\frac {-7}6 = \frac{-8n}{6}$$
So it must be that $-7$ and $-8n$ are the same thing:
$$-7=-8n$$
$$n=\frac{-7}{-8}$$
$$n=\boxed{\dfrac 78}$$
A: All other answers are way too complicated. You have:
$$-\frac76=-\frac {4n}{3}$$
Therefore:
$$\frac76=\frac {4n}{3}$$
Equivalently:
$$\frac76=\frac {8n}{6}$$
So:
$$7=8n$$
Thus:
$$n = \frac 7 8$$
