Probability of Sets I need some help on this one:
We have sets $X$ and $Y$ chosen independently and uniformly at random from among all subsets of $\{1,2,\ldots,100\}$. Determine the probability that $X$ is a subset of $Y$.
 A: how many pairs $(X,Y)$ satisfy $X\subseteq Y$? classify according to the size of $Y$.
So we get $\sum\limits_{k=0}^n\binom{n}{k}2^k$.
Since there are $2^n\times 2^n$ possible pairs $(X,Y)$ you want $$\frac{\sum\limits_{k=0}^n\binom{n}{k}2^k}{2^{2n}}$$
Now notice that $\sum\limits_{k=0}^n\binom{n}{k}2^k$ is equal to $3^n$ because it is the number of ways to color the integers from $1$ to $n$ with colors white grey and black. To see this we could say we are indexing on the number of elements that are grey or black (So first pick the subset of numbers that are grey or black) And once that subset has been selected choose the subsets of that subset that is going to be black. Hence uniquely determining the coloring.
A: For every element $a$ of initial set one of four options is true:  


*

*$\quad a \in X,\quad a \in Y$

*$\quad a \not\in X,\quad a \in Y$

*$\quad a \in X,\quad a \not\in Y$

*$\quad a \not\in X,\quad a \not\in Y$


The probability of each option is $1/4$ (due to independence and uniformity).
$X\subseteq Y$ if for all $a \in \{1,\ldots,100\}$ options number $1$, $2$ or $4$ are true. For every element probability is $\dfrac{3}{4}$ and for whole set it is $\left(\dfrac{3}{4}\right)^{100}$.
A: Let $D_n = \{i| i \in \Bbb N \land i \le n\}$.
For an empty set $D_0$ all its subsets $X,Y \subseteq D_0$ are empty: $X = Y = \emptyset$, so $P_0(X\subseteq Y) = 1.$
Now let's consider $D_n$ for $n\in \Bbb N$. Then any subset $X\subseteq D_n$ either is a subset of $D_{n-1}$ or it contains the number $n$, both with probability equal $\tfrac 12$. For subsets $X,Y$ there are four equally possible cases of $n$ inclusion, which results in $$P_n=\tfrac 14P_{n-1} + 0 + \tfrac 14P_{n-1} + \tfrac 14P_{n-1} = \tfrac 34P_{n-1} $$
Since $P_0 = 1 = \left(\tfrac 34\right)^0$, the above makes a general answer $$P_n=\left(\tfrac 34\right)^n$$
