For an arbitrary $x_{0}$ in $\left(\, 0,\pi\,\right)$ we define $x_{n + 1}=\sin\left(\, x_{n}\,\right)$.
Using the limit of the sequence as $n$ tends to infinity we're supposed to find the limit of $\,\sqrt{\,n\,}\,\sin\left(\,x_{n}\,\right)$ .
I literally don't know where to start, any ideas ?.