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I understand that the Fourier transforn gets you the function which gives the amplitude of each frequency. But I don't understand how that is possible by multiplying it by an exponential. How is that possible?

EDIT: Since my question seems to be unclear: how do you get the amplitude of a frequency f, by integrating it and multiplying it with exp(-i*2*Pi*f) ?

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  • $\begingroup$ What do you mean when you say "by multiplying it by an exponential"? I don't understand your question. What is being multiplied? $\endgroup$ – NicNic8 Jan 1 '15 at 7:35
  • $\begingroup$ @NicNic8 I mean the Fourier transform itself (multiplying with an exponential and integrating over R). How does that get you to the frequency domain? $\endgroup$ – Alexander Cogneau Jan 1 '15 at 7:38
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Let's look at the equation of the Inverse Fourier Transform. $$f(x)=\int_{-\infty}^{\infty}F(s)\text{e}^{i2\pi sx}ds$$ The integral is "like" a summation, so let's replace it with a summation to make it easier. $$f(x)=\sum_{s=-\infty}^{\infty}F(s)\text{e}^{i2\pi sx}\Delta s$$ We've approximated the integration with a Riemann sum. This is not necessary, but maybe it makes things a bit easier to see. We can rewrite this using Euler's identity. $$f(x)=\sum_{s=-\infty}^{\infty}F(s)\left(\cos(2\pi sx)+i\sin(2\pi sx)\right)\Delta s$$ So we see that our function $f$ is really just a sum of a bunch of sinusoids. What are the frequencies of these sinusoids? And what are their amplitudes? Recall that the function $g(x)=A\cos(\omega x)$ has frequency $\omega$ with amplitude $A$

So we see that the frequencies of the sinusoids are $2\pi s$ and the amplitudes are $F(s)$.

$F$ is often called the spectrum of the function $f$.

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  • $\begingroup$ I see how this works now, but how about the other way around? How does the integration get you the amplitude? $\endgroup$ – Alexander Cogneau Jan 1 '15 at 8:57
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So what is the definition of the Fourier Transform? The definition is as follows: $$F(s)=\int_{-\infty}^{\infty}f(x)\text{e}^{-i2\pi sx}dx$$ What is the definition of the inverse Fourier Transform? It's very similar, and is as follows: $$f(x)=\int_{-\infty}^{\infty}F(s)\text{e}^{i2\pi sx}ds$$ Note that there are other equivalent definitions, but we will work with these.

So where does frequency come into the picture? People often call $s$ the frequency. Integration is "like" a summation. Euler's identify is also relevant: $\text{e}^{ia}=\cos(a) + i\sin(a)$. So $\text{e}^{i2\pi sx}=\cos(2\pi sx)+i\sin(2\pi sx)$. So $2\pi s$ is the frequency of the co/sinusoid. And what is the amplitude of that sinusoid? It's $F(s)$.

The function $F$ is often called the "spectrum" of $f$.

Does this help?

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  • $\begingroup$ Yes I knew that already. My question was, how does it come that F(s) gets you the amplitude of the s frequency? $\endgroup$ – Alexander Cogneau Jan 1 '15 at 7:52
  • $\begingroup$ I tried answering again. Please see the other answer that I gave. $\endgroup$ – NicNic8 Jan 1 '15 at 8:21

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