Evaluate $\iint z \cos \gamma \, dS$, over the outside of the $unit$ $sphere$ centred at origin, where γ is the inclination of the normal surface at any point of the $unit$ $sphere$ with the z-axis.
How do I deal with this $\gamma$ term? I know for a point $(x,y,z)$ on the unit sphere $\cos \gamma = z$. So can I replace the term $z \cos \gamma$ by $z^2$? I am confused about this because the $z$ in the integrand is a scalar function and not a point on the surface.
How do I proceed with this integration. Please help.