Let $I\subset A$ be a ideal of a Banach algebra $A$. Assume $p\in \overline I$ and $p^2=p$.
Show: $p\in I$.
Can someone give me a little hint how to solve this, please?
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It only takes a minute to sign up.
Sign up to join this communityLet $I\subset A$ be a ideal of a Banach algebra $A$. Assume $p\in \overline I$ and $p^2=p$.
Show: $p\in I$.
Can someone give me a little hint how to solve this, please?
This is recorded as Lemma 2.7 in
Niels Jakob Laustsen, Thomas Schlumprecht, and András Zsák, The lattice of closed ideals in the Banach algebra of operators on a certain dual Banach space, J. Operator Theory 56 (2006), no. 2, 391–402.
I assume that $A$ is unital, if not, we can pass to the unitisation.
Suppose that $(t_n)_{n=1}^\infty$ is a sequence in $I$ that converges to an idempotent $p$. Since $pAp$ is a Banach algebra with identity $p$ and $pt_np \to p^3=p$, there exists $n$ so that $pt_np$ is invertible in $pAp$. Consequently, $p = (psp)(pt_np)$ for some $s\in A$. This proves that $p\in I$.