Odd-Order Groups with Cyclic p-Sylow Subgroups (for smallest p | G) I am a beginner in group theory and I'm looking for finite groups that satisfy some properties.
The only example I've found so far is:
$$G_{q,c} = \{ f: \mathbb{F}_{q} \to \mathbb{F}_{q}, z \mapsto az+b | b \in \mathbb{F}_{q}, a \in (\mathbb{F}_{q}^{\times})^c \}$$
For $c$ such that $\frac{q-1}{c}$ is odd.
The properties are:


*

*$G$ has odd order and is not abelian. (The most important requirement)

*Let $p$ be the smallest prime dividor of $|G|$. The $p$-Sylow groups of $G$ must be cyclic.


As so many famous non-abelian groups are of even order, I find it hard to find such groups. I would be glad to see some more examples.
EDIT: I've just realized that since every group of prime order is cyclic, the 2nd property is satisfied once $p$ divides $|G|$ exactly once.
 A: Take any two different odd primes $\;p\,,\,q\;$ . s.t. $\;p>q\;,\;\;q\mid(p-1)\;$ . Take two cyclic groups $\;C_p=\langle\,y\,\rangle\,,\,\,C_q=\langle\,x\,\rangle\;$ of order $\;p\,,\,\,q\;$ , resp.
Then you can build a(n exterior)  semidirect product $\;C_q\rtimes C_p\;$ by means of the homomorphism 
$$\;f: C_q\to \text{Aut}\,(C_p)\;,\;\;f(x):=\phi_q$$
where $\;\phi_q\;$ is the automorphism of order $\;q\;$ of $\;C_p\;$
You get a non-abelian group of odd order and such that all its Sylow subgroups are cyclic (and even of prime order)
A: One thing that you may have overlooked is that for any prime $q$ there is an enormous amount of non-abelian $q$-groups, so take one, call it $Q$, and all direct products $\mathbf C_{p^i} \times Q$ will qualify provides $p<q$.
In fact this is just one instance of the following generalization of your construction.
Let's say a group satisfies $\star_p$ if it satisfies your conditions with the exception of being non-abelian.


*

*Take any group $G$ such that the least prime dividing its order is $q>p$.

*Let $A$ be any group satisfying $(\star_p)$.

*Take any morphism $\theta: A\to\mathrm{aut}(G)$.


Then $G\rtimes_{\theta} A$ satisfies $(\star_p)$. Moreover, if at least one of these conditions is fulfilled then the group will be non abelian and satisfy your conditions.


*

*$G$ is non-abelian

*$A$ is non-abelian

*$\theta$ is non-trivial. 


So this provides an inductive way of creating more and more of this type of groups. 
For instance, it's clear that this is $G_{q,c}$ arises by starting with $G$ and $A$ both cyclic.  (In fact every $\star_p$-group arises trivally by setting $G=1$ although this is not very interesting.)
Other example: by choosing $\theta$ trivial you find the example that I started this answer with; in particular if $A=G_{q,c}$ you will for instance find examples of the type $G_{p,c} \times G$ where $G$ is not divisible by primes larger than $p$.
More examples can be found by starting with $A=\mathbf C_p^i$ and $G$ any $q$-group for a prime $p>q$, for instance any abelian group having an automorphism of order a power of $p$, or a Heisenberg group (where $\theta$) can be trivial, etc, etc.
