# Multiplying with Polynomials.

In $(3xy)^2$, do I distribute that power of two to each of the terms?

$(3^2)\times(x^2)\times(y^2) = 9x^2y^2$?

Or do I just treat it as $3xy^2$?

• The first option. – Edward Jiang Dec 19 '14 at 2:28
• $3^2 \cdot x^2 \cdot y^2 \; = \; 9x^2y^2$ – mathamphetamines Dec 19 '14 at 2:29
• you have computer so search it up. on google – Irrational Person Dec 19 '14 at 2:31
• I am searching it up, right here. ._. – John Dec 19 '14 at 2:32

$$(3xy)^2 = (3xy)(3xy) = 3\cdot 3\cdot x\cdot x\cdot y\cdot y = 3^2x^2y^2=9x^2y^2$$
All terms. $(3xy)^2=(3xy)(3xy)=(9x^2y^2)$
Good time to note how it's important to put those parentheses around expressions like this to distinguish $(3xy)^2$ from $3xy^2$