How is the following graph a weakly connected graph?

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1 Answer 1


The concept of "strongly connected" and "weakly connected" graphs are defined for directed graphs.

A digraph is strongly connected if every vertex is reachable from every other following the directions of the arcs. I.e., for every pair of distinct vertices $u$ and $v$ there exists a directed path from $u$ to $v$.

A digraph is weakly connected if when considering it as an undirected graph it is connected. I.e., for every pair of distinct vertices $u$ and $v$ there exists an undirected path (potentially running opposite the direction on an edge) from $u$ to $v$.

In both cases, it requires that the undirected graph be connected, however strongly connected requires a stronger condition. You also have that if a digraph is strongly connected, it is also weakly connected.

In your example, it is not a directed graph and so ought not get the label of "strongly" or "weakly" connected, but it is an example of a connected graph. As soon as you make your example into a directed graph however, regardless of orientation on the edges, it will be weakly connected (and possibly strongly connected based on choices made).

  • $\begingroup$ thanks, helped me a lot! $\endgroup$ Dec 10, 2018 at 18:56

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