How to fully factor this polynomial? $$ 2x^4+3x^3-32x^2-48x$$
Can anyone describe the full steps to factor it? Thanks for the help.
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$$2x^4+3x^3-32x^2-48x$$ $$=x(2x^3+3x^2-32x-48)$$ $$=x(x^2(2x+3)-16(2x+3))$$ $$=x(2x+3)(x^2-16)$$ $$=x(2x+3)(x-4)(x+4)$$