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How to fully factor this polynomial? $$ 2x^4+3x^3-32x^2-48x$$

Can anyone describe the full steps to factor it? Thanks for the help.

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    $\begingroup$ There is a general formula for a 4th order polynomial, but it is way too long to remember. Just try to guesstimate two solutions and then quadratic formula the rest. I'm sorry I can't be more specific. $\endgroup$ Dec 13, 2014 at 22:38
  • $\begingroup$ haha +1 for guesstimate:D $\endgroup$
    – Marc
    Dec 13, 2014 at 22:41
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    $\begingroup$ As Edward has shown, there is not need for the quartic formula or guestimation. Cubic polynomials $ax^3+bx^2+cx+d$ (which this becomes when an $x$ is factored out) are easily factorable when $a/c=b/d$ or $a/b=c/d$. $\endgroup$ Dec 13, 2014 at 23:20

1 Answer 1

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$$2x^4+3x^3-32x^2-48x$$ $$=x(2x^3+3x^2-32x-48)$$ $$=x(x^2(2x+3)-16(2x+3))$$ $$=x(2x+3)(x^2-16)$$ $$=x(2x+3)(x-4)(x+4)$$

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