Let $X_0$ be a variety over $\mathbf{F}_q$. Consider the Frobenius $F_0:X_0\to X_0$. Let $X= X_0\times \bar{\mathbf{F}_q}$ and let $F:X\to X$ be $F_0 \times \textrm{id}$.

Let $f:X\to X$ be an automorphism of finite order. Is $F\circ f$ the Frobenius with respect to some new way of lowering the base field to $\mathbf{F}_{q}$?

  • 1
    $\begingroup$ Could you make more precise your question ? $\endgroup$ – user18119 Feb 22 '12 at 12:29

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.