Riemann Mapping Theorem, the concept of a Riemann mapping If I construct a composition of mappings that map the upper half of the unit disk conformally to the entire unit disk, then this mapping is a Riemann mapping, by the Riemann Mapping Theorem, since $D^+$ is simply connected and not the entire complex plane.
My question is:  is a conformal mapping from the upper half plane to the (open) unit disk considered a Riemann mapping?  What about a conformal mapping from, say, the first quadrant, to the unit disk?  Naively, I'd say that these are simply connected regions that are not the entire complex plane.
My guess is that, because these pre-image regions include the point at infinity, they are somehow equivalent to being the entire complex plane - and perhaps this is more of just knowing what the Riemann sphere is?  (Thus, these are not Riemann mappings.)
And, by this logic, then a mapping of a vertical or horizontal strip to the unit disk is not a Riemann mapping either.
 A: 
this mapping is a Riemann mapping, by the Riemann Mapping Theorem, 

The Riemann Mapping Theorem does not say how the map is called. It says that it exists.  How to call it is a matter of conventions and definitions, not theorems.  The convention I am familiar with is (as on Riemann mapping theorem wiki page): 

Riemann mapping = a holomorphic bijective map of a simply-connected domain onto the unit disk. 

Riemann mapping theorem is a statement that such a thing exists for every simply-connected domain in $\mathbb C$, except $\mathbb C$ itself. 


What about a conformal mapping from, say, the first quadrant, to the unit disk? Naively, I'd say that these are simply connected regions that are not the entire complex plane.

Correct. 

these pre-image regions include the point at infinity

Incorrect. They are unbounded, but they do not include the point at infinity because their complement is also unbounded. In terms of the Riemann sphere,   $\infty$ is one of their boundary points.

a mapping of a vertical or horizontal strip to the unit disk is not a Riemann mapping either.

It is. These are simply-connected domains of the complex plane. They do not contain the point at infinity. 
