This is probably a silly question but I am just not sure if I understand what to do.

So I have the parametric equations:

$x=6\cos (t)-2\\ y=5\sin (t)+3$

I am asked to compute $\dfrac{dy}{dx}$ at the point $(3\sqrt{2}-2, 3-\frac{5}{\sqrt{2}})$

So $$\frac{dy}{dx}=\frac{\frac{dy}{dt}}{\frac{dx}{dt}}\implies\frac{dy}{dx}=-\frac{5\cos(t)}{6\sin(t)}$$

Now where do I plug the above numbers in to find $\dfrac{dy}{dx}$? Am I on the right track?


1 Answer 1


Hint: $\cos t = \dfrac{x+2}{6}$, and $\sin t = \dfrac{y-3}{5}$

  • $\begingroup$ Ah ha! Thank you very much! I will accept your answer as soon as it lets me! $\endgroup$
    – FofX
    Commented Nov 19, 2014 at 4:23

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .