Is the below the correct partial fraction decomposition?
$$\frac{s^2 - 6s + 9}{(s-2)^3}=\frac{A}{s-2}+\frac{B}{(s-2)^2}+\frac{C}{(s-2)^3}$$
I can see that the numerator doesn't have a factor of $(s-2)$ so I can't see how I can simplify it any further. But I wasn't sure if that is the proper method for decomposing the factors on the next denominators.
Thank you.