I'm having trouble solving this equation..
$$\int_0^{e-1}\frac{1}{x+1}\,\mathrm dx$$
I have tried the substitution method with $u= x+1$ and $du= 1dx$
$$\int_\ udu$$
then I get $$\left.\frac{u^2}{2}\right|_0^{e-1}$$ then I change the $u$ to $x+1$
$$\left.\frac{(x+1)^2}{2}\right|_0^{e-1}$$
When I solve for $F(e-1)-F(0)$, I am stuck.
Did I set this equation correctly? Please help me understand how to solve this equation? My professor has provided me with the answer but I don't know how he had gotten the answer. The answer to the equation is $1$.