Let $S$ be a smooth complex projective surface. A Lefschetz pencil over $S$ is a rational map (which is not a morphism) $f:S--\rightarrow\mathbb P^1_{\mathbb C}$ with the following property:
All but finitely many fibers of $f$ are smooth and the singular fibers have only an ordinary double point and no more singularities.
The finite set of points $B\subseteq S$ where $S$ is not defined is called the base locus.
I'd like to see the sketch of the proof of the following theorem:
For every non singular complex projective surface there exists a Lefschetz pencil (the base locus must be non-empty)
I need to find a particular linear system $|D|$ on $S$ such that the induced rational map on $\mathbb P^1_{\mathbb C}$ is a Lefschetz pencil; but the problem is the following: how can I choose $|D|$?
Many thanks
longrightarrow
) or has it some special meaning? $\endgroup$