Are two matrices similar if and only if they have the same Jordan Canonical form?

Does the Jordan form have to have ordered eigenvalues?

For example, if $\lambda_1$ and $\lambda_2$ are eigenvalues of $A$, are $\begin{pmatrix}\lambda_1&0\\0&\lambda_2\end{pmatrix}$ and $\begin{pmatrix}\lambda_2&0\\0&\lambda_1\end{pmatrix}$ both Jordan forms of $A$?

  • Up to arbitrary ordering of Jordan blocks, yes
  • No
  • Yes
  • $\begingroup$ Thanks! That really cleared my problem up! $\endgroup$ – Dia McThrees Nov 11 '14 at 22:30

The eigenvalues need not be ordered. You can conjugate a diagonal matrix by a permutation matrix to put them in any order.


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