Primes for which a polynomial splits completely Suppose that $f(x) \in \mathbb{Z}[x]$ is an irreducible polynomial over $\mathbb{Q}$. Nevertheless, it may be the case that $f(x)$ is reducible modulo $p$ for some prime $p$. What is the density of primes $p$ for which $f(x)$ splits completely into linear factors over $\mathbb{F}_p$?
 A: The density is $\frac{1}{|G|}$ where $G$ is the Galois group of $f$. In particular it is at least $\frac{1}{(\deg f)!}$. This is a corollary of the Frobenius density theorem, a slightly weaker but (apparently; I don't know this first-hand) considerably easier version of the Chebotarev density theorem. 
For example, let $f(x) = \Phi_n(x)$ be the $n^{th}$ cyclotomic polynomial. The primes for which $f(x)$ splits are precisely the primes congruent to $1 \bmod n$; the density of these is $\frac{1}{\varphi(n)}$ by Dirichlet's theorem on arithmetic progressions. And indeed the Galois group is $(\mathbb{Z}/n\mathbb{Z})^{\times}$, which has size $\varphi(n)$. 
A: A full answer would be Chebotarev density for, well, anything. What I do know are some examples; if $$ f(x) = x^3 - x + 1, $$ the density is $(1/6).$ The primes are those which can be expressed as 
$$ p = u^2 + uv + 6 v^2.  $$ Plenty more where that came from. Quoting from page 188 of Cox, Theorem 9.12, as well as a 1991(?) paper by Williams and Hudson.
EDIT, Monday Nov. 10; I got very interested in the history of this for my own reasons. One direction about different cycle partitions in the Galois group, considered as a permutation group, is attributed entirely to Dedekind, see COX. So, if, for any prime not dividing the discriminant, the polynomial factors with a certain partition of irreducible factor degrees, then there is at least one element in the Galois group whose cycle description is the same. 
The Frobenius direction, about the same time (1880-1900) is that, once the Galois group has an element with a certain cycle decomposition, then infinitely many primes cause the polynomial to factor with that pattern, this set of primes has both a Dirichlet density and a natural density, and the density is the number of Galois group elements with that pattern divided by the size of the full Galois group. Note that, as Qiaochu mentions, there is only one element (the identity) that has all cycles of length $1,$ the identity element. 
Oh; most people seem to quote one source about Frobenius Density, a survey by Lenstra and Stevenhagen, especially pages 10-12 in the preprint linked. 

The theorem of Frobenius ...deserves to be better known than it is.
  For many applications...it suffices to have Frobenius's theorem, which
  is both older (1880) and easier to prove..

I think this is lovely. Proof in an undergraduate course would be another matter, showing there is a natural density came later.  
