3 students each choose two problems from a list of eight problems. How many ways can this be done?
The answer in the text book gives 8!/(2! 2! 2! 2!), but don't we also have to multiply by the number of ways the questions can be assigned to each student? So 3! x 8!/(2! 2! 2! 2!)?
Please help me understand what I have misunderstood. THANKS!