$$X\sim\mathrm{binomial}(1, 1/3)\text{ and }Y\sim\mathrm{binomial}(2,1/2)$$
How can I get
$$W = XY+1$$
Normally I would attempt but this one I don't even know how to get started
$$X\sim\mathrm{binomial}(1, 1/3)\text{ and }Y\sim\mathrm{binomial}(2,1/2)$$
How can I get
$$W = XY+1$$
Normally I would attempt but this one I don't even know how to get started
$$ \begin{array}{c|ccc|c} X \backslash Y & \ 0 & \ 1 & \ 2 & \ \\ \hline 0 & 1 & 1 & 1 & \ 2/3 \\ 1 & 1 & \fbox{2} & 3 & \fbox{1/3} \\ \hline & \ (1/2)^2 & \ \fbox{$2(1/2)^2$} & \ (1/2)^2 & \mathbb{Pr}(Y) \backslash \mathbb{Pr}(X) \\ \end{array} $$
From the above table we see that $\mathbb{Pr}(W=2) = \mathbb{Pr}(X=1,Y=1) = 2(1/2)^2(1/3)=1/6.$
Can you do the rest?