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A bucket contains $2$ red, $3$ white and $4$ blue balls. If you randomly pick(without putting the balls back) $2$ balls, how great is the chance that the picked balls have different colors?

I really don't know how to get started on this.

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  • $\begingroup$ What are your thoughts on the problem? $\endgroup$
    – Servaes
    Sep 30, 2013 at 9:38

2 Answers 2

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Hint: compute the probability you got two balls of the same colour for each possible colour.

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  • $\begingroup$ Thanks for the hint mau, it really helped me so much! Chance of picking 2 red balls: 2/9*1/8 = 2/72. Chance of picking 2 white balls: 3/9*2/8 = 6/72. Chance of picking 2 blue balls: 4/9*3/8 = 12/72. Total: = 20/72. Negation: 1-total= 52/72. $\endgroup$
    – Martin
    Sep 30, 2013 at 9:53
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D stands for different colour. Then you have the possibilities RD,WD and BD. (B=blue et cetera).

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