3
$\begingroup$

I have recently started out with series and I have a few set of questions.

Consider, $$\sum\limits_{k=p}^{q} f(k) $$

  1. How is the notation read as? Like summation $k = p $ to $q$ or Sigma $k=p$ to $q$.

  2. Why (I want to know the reason pls) should $k$ always be an integral value?

  3. Can $k$ take negative values like $-3$, $-7$? or fractional values like $ \frac{1}{2} $ etc?

I tried googling but all I found was all sorts of irrelevant or advanced stuffs. Please use laymen terms :)

$\endgroup$
2
  • $\begingroup$ You can read it either way, as they both mean the same thing $\endgroup$ Jun 6, 2018 at 15:10
  • $\begingroup$ Or sometimes more like English: "sum $f(k)$ for $k$ from $p$ to $q$". $\endgroup$ Jun 6, 2018 at 15:18

2 Answers 2

2
$\begingroup$
  1. makes no difference, pick whatever is more convenient
  2. we usually think of $\sum$ as a discrete operator, letting $k$ be real, for example, will transform it into a continuous one, alike the $\int$.
  3. As is clear from (2), $k$ can take values in any discrete set, but the convention is to have it vary over subsets of integers. So you may encounter $$ \sum_{x \in A} f(x). $$
$\endgroup$
0
$\begingroup$

How is the notation read as? Like summation k=p to q or Sigma k=p to q.

Sigma f(k), from p to q.

Why (I want to know the reason pls) should k always be an integral value?

This is by the definition of $\sum $ notation for adding countable quantities.

Can $k$ take negative values like −3, −7? or fractional values like 1/2 etc?

Yes, you cans start with negative integers as well, but not fractions.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .