Let $f : [0,1] \to \mathbb{R}$ be continous and define the operator $T$ in the following way
$$Tf(x)=\frac{1}{\sqrt{\pi}} \int_0^x \frac{f(t)}{\sqrt{x-t}} \, \text{d}t \, . $$
(i) Prove $Tf$ is continuous on $[0,1]$.
(ii) Prove that $$T^2f(x)= \int_0^xf(t)\,\text{d}t\,, \ \ \ \forall x \in [0,1]\,. $$
I think I got the first part, using the limit under the integral sign theorem. However, I am stuck on part (ii).