Let $(R,m)$ be a commutative local Noetherian ring and $M$ a finitely generated $R$-module. I want to show that $\operatorname{Tor}_{n+1}(M,R/m)=0$ if and only if $\operatorname{Ext}^{n+1}(M,R/m)=0$.
I know that $\operatorname{Tor}_{n+1}(M,R/m)=0$ if and only if the projective dimension of $M$ is less than equal to $n$. So $\operatorname{Tor}_{n+1}(M,R/m)=0$ implies $\operatorname{Ext}^{n+1}(M,R/m)=0$.
By using induction on $n$, the converse reduces to the case $n=0$. But I can't prove it.
Does anyone have a good idea for this?