9
$\begingroup$

In most case, the definition of a variety over a field $k$ at least requires that being "of finite type" and being "separated". It has no question for me that being of finite type, since we always like finite.

I donot know the reason why we require being "separated" to a variety?

There is a reason since a scheme over a field $k$ being separated will have the property that the intersection of two affine open sets is still affine open set.

Are there any other acceptant reasons?

Thanks a lot.

$\endgroup$

2 Answers 2

9
$\begingroup$

Separatedness is the analogue in the Zariski topology of Hausdorfness in the cohmology of a manifold or complex analytic space. Without it, strange behaviour can occur. E.g. if $Y$ is not separated, then two morphisms $f,g: X \to Y$ could coicide on a dense open subset of $X$ while not coinciding on all of $X$. Hence "analytic continuation'' is not valid for morphisms into $Y$.

Many arguments in geometry proceed by analytic continuation/Zariski density arguments, so it is natural to place oneself in a context where those arguments can be applied without reservation.

$\endgroup$
1
$\begingroup$

Besides what Matt E has explained, if you include the separatedness in the definition of scheme i.e. as a separated (having closed diagonal) prescheme, the analogy will be more clear in this respect that a variety is in fact, a separated prevariety where prevariety by this definition is an irreducible, reduced prescheme of finite type over an algebraically closed field $k.$ This approach is closer to the way, Mumford in Red book of varieties and schemes has adopted to define the notion of variety.

$\endgroup$
2
  • 2
    $\begingroup$ Right, but nowadays we do not include separatedness in the definition of a scheme: that is preschemes no longer exist. To the extent that I am qualified to have opinions on such matters, I do think the terminology "prescheme" was poor, because -- e.g. compare with "presheaf" -- it suggests that the first thing we should do is apply some completion functor to get a scheme. But in moduli theory one does (unfortunately!) sometimes encounter nonseparated schemes/stacks, and I'm pretty sure that "scheme-ifying it" is not the thing to do. $\endgroup$ May 12, 2012 at 19:10
  • $\begingroup$ @Pete L.Clark: I admit that, prescheme is old fashioned these days, but I just wanted to note that it fits nicely to the hierarchy of AG definitions. $\endgroup$ May 12, 2012 at 19:20

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .