What is the value for $\lim \limits _{x\to\infty} \frac{\sin x} x$?
I solved it by expanding $\sin x$ as
$$\sin x = x - \frac {x^3} {3!} \dotsc$$
So $\lim \limits _{x\to\infty} \frac {\sin x} x = 1 -\infty = - \infty$,
but the answer is $0$. Why? What I am doing wrong?