Reputation
1,734
Top tag
Next privilege 2,000 Rep.
Edit questions and answers
Badges
10 50
Impact
~61k people reached

Aug
4
comment Area of a polygon
Its very hard to figure out the answer, without knowing whether you are looking at a regular or irregular polygon . But I think that typing " derive area of polygon " in Google may fetch you lots of links. Prefer Google before moving your question to Math.SE. Thank you.
Aug
4
comment How does a Class group measure the failure of Unique factorization?
Thank you for your answer. But what does the exact quotient group mean ? I had a tough time in understanding what does one get when one looks at quotient group. Suppose we are having { Fractional Ideals of F } / { Principal fractional ideals of F }. Then what are we looking at exactly ? . Every ideal is a principal ideal , i.e every ideal can be written as $I=\alpha.(1)$ . Doesn't it imply that every ideal is principal ? Forgive me if I am wrong.
Aug
4
comment How does a Class group measure the failure of Unique factorization?
Thanks a lot for your edit Mr. M Turgeon
Aug
4
comment Karatsuba Multiplication
@mixedmath : Perfect answer, I was going to type what you have added in the comment, and you saved my effort of typing again , Thanks . But to add something, David, this types of strategies fall under something called " [Divide and conquer strategies ](en.wikipedia.org/wiki/Divide_and_conquer_algorithm) , where you divide the initial problem into pieces and later on assemble them into a the original problem. Rest of the thing is neatly explained in mixedmath's version.
Aug
4
revised How does a Class group measure the failure of Unique factorization?
added something
Aug
4
comment How does a Class group measure the failure of Unique factorization?
Thanks a lot for your answer. +1
Aug
4
comment How does a Class group measure the failure of Unique factorization?
Good answer, Thank you sir +1
Aug
4
asked How does a Class group measure the failure of Unique factorization?
Aug
3
comment Original works of great mathematician Évariste Galois
Great answer indeed. Thank you. @WillJagy : Thank you for your links sir.
Jul
28
accepted Can the order of learning be changed?
Jul
28
comment Are the solutions of $x^{x^{x^{x^{\cdot^{{\cdot}^{\cdot}}}}}}=2$ correct?
@AndréNicolas : Is it advisable if I can ask another separate question stating all these things, so that you can answer that elaborately . But anyway your comment is quite good and I thank you for that.
Jul
28
comment Are the solutions of $x^{x^{x^{x^{\cdot^{{\cdot}^{\cdot}}}}}}=2$ correct?
@AndréNicolas : But sir, a small doubt. How can one believe that $\sqrt{2}^{\sqrt{2}^{\sqrt{2}^\cdots }}= 2 ? $. Why should one believe that, and what is the intuition . Can you throw some light ?
Jul
27
comment Obtain a contradiction
@GerryMyerson : Yes, thank you for teaching me the responses trick, which I don't know previously. Its true that professor wanted me to solve but I was stuck some-where. I can't proceed further. I never asked you to solve it completely , but instead I wanted someone to post some ideas/hints in that direction.
Jul
27
comment Can dividing two rational numbers yield an integer?
@MistyD : Simply to state $a=n*b$ then it means $ b | a $ for some $n \in \mathbb{z}$
Jul
27
comment Can dividing two rational numbers yield an integer?
@MistyD : .. Contd . 1) Start with $ K= \dfrac{a}{b}$. 2)$ M= \rm{G.C.D}(a,b) $3 ) $K=\dfrac{\dfrac{a}{M}}{\dfrac{b}{M}}$. Recursively repeat until it yields an integer 4) If it don't yield an integer take the new numerator and new denominator, if their G.C.D is 1 , then its division will not be an integer. Or else it would be an integer.
Jul
27
comment Can dividing two rational numbers yield an integer?
@MistyD : That don't work always. I wanted to edit further, but suddenly my internet was interrupted. Anyway you will not get an integer always when G.C.D is not 1. Suppose $\dfrac{42}{56}=\dfrac{3}{4} \notin \mathbb{Z}$ . But $\rm{G.C.D(42,56)}=14$. So here are few steps you need to work out. 1) See that numerator is always greater or equal to denominator. 2) Reduce the fraction to the least form by applying recursive cancellations. A pseudo code can be as follows. Contd..
Jul
27
comment Can dividing two rational numbers yield an integer?
@MistyD : Its not the point of integers or rationals. Its the point of G.C.D . If the numerator and denominator have a G.C.D of 1, they wont yield integers and leave you with some decimal part
Jul
27
comment Obtain a contradiction
@OldJohn : Its simply a Diophantine equation. I was asked to solve it by a professor. I don't think there will be some motivation behind choosing some equations. For example, why does we need to know $x^n+y^n \neq z^n $ when $n\gt2$ ? .
Jul
27
comment Obtain a contradiction
@GerryMyerson : I have now added the motivation sir. I beg you to use '@' while posting comments, I didn't see the comment from many weeks, and that's why I didn't edit it so far. Now I have done by your kind suggestion. Thank you for that.
Jul
27
revised Obtain a contradiction
added something