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I am Iyengar, and I hail from South India, from a rural city. I have completed my engineering in computer science, but I was always interested in advanced physics, mathematics, philosophy and cognition and evolutionary theories. Because I barely have any teacher along with me to teach me, and no proper library, I did quite a bit of self learning from the internet, and roughly learned many diverse concepts, starting from Quantum mechanics, to Algebraic geometry, Galois theory, philosophy and cognition. I didn't have a path so I dumped down all the knowledge that was available before me. I had generated some ideas to solve Millennium prize problems and some ideas in Quantum mechanics, which have to be made concrete, and since I didn't have a proper channeling, all my ideas and work went unnoticed.

Nevertheless I continue to go further, seeking knowledge. Knowledge is power.


Jul
28
comment Are the solutions of $x^{x^{x^{x^{\cdot^{{\cdot}^{\cdot}}}}}}=2$ correct?
@AndréNicolas : Is it advisable if I can ask another separate question stating all these things, so that you can answer that elaborately . But anyway your comment is quite good and I thank you for that.
Jul
28
comment Are the solutions of $x^{x^{x^{x^{\cdot^{{\cdot}^{\cdot}}}}}}=2$ correct?
@AndréNicolas : But sir, a small doubt. How can one believe that $\sqrt{2}^{\sqrt{2}^{\sqrt{2}^\cdots }}= 2 ? $. Why should one believe that, and what is the intuition . Can you throw some light ?
Jul
27
comment Obtain a contradiction
@GerryMyerson : Yes, thank you for teaching me the responses trick, which I don't know previously. Its true that professor wanted me to solve but I was stuck some-where. I can't proceed further. I never asked you to solve it completely , but instead I wanted someone to post some ideas/hints in that direction.
Jul
27
comment Can dividing two rational numbers yield an integer?
@MistyD : Simply to state $a=n*b$ then it means $ b | a $ for some $n \in \mathbb{z}$
Jul
27
comment Can dividing two rational numbers yield an integer?
@MistyD : .. Contd . 1) Start with $ K= \dfrac{a}{b}$. 2)$ M= \rm{G.C.D}(a,b) $3 ) $K=\dfrac{\dfrac{a}{M}}{\dfrac{b}{M}}$. Recursively repeat until it yields an integer 4) If it don't yield an integer take the new numerator and new denominator, if their G.C.D is 1 , then its division will not be an integer. Or else it would be an integer.
Jul
27
comment Can dividing two rational numbers yield an integer?
@MistyD : That don't work always. I wanted to edit further, but suddenly my internet was interrupted. Anyway you will not get an integer always when G.C.D is not 1. Suppose $\dfrac{42}{56}=\dfrac{3}{4} \notin \mathbb{Z}$ . But $\rm{G.C.D(42,56)}=14$. So here are few steps you need to work out. 1) See that numerator is always greater or equal to denominator. 2) Reduce the fraction to the least form by applying recursive cancellations. A pseudo code can be as follows. Contd..
Jul
27
comment Can dividing two rational numbers yield an integer?
@MistyD : Its not the point of integers or rationals. Its the point of G.C.D . If the numerator and denominator have a G.C.D of 1, they wont yield integers and leave you with some decimal part
Jul
27
comment Obtain a contradiction
@OldJohn : Its simply a Diophantine equation. I was asked to solve it by a professor. I don't think there will be some motivation behind choosing some equations. For example, why does we need to know $x^n+y^n \neq z^n $ when $n\gt2$ ? .
Jul
27
comment Obtain a contradiction
@GerryMyerson : I have now added the motivation sir. I beg you to use '@' while posting comments, I didn't see the comment from many weeks, and that's why I didn't edit it so far. Now I have done by your kind suggestion. Thank you for that.
Jul
27
revised Obtain a contradiction
added something
Jul
27
comment Obtain a contradiction
@GerryMyerson : There is no motivation sir. My plan was to prove that the equation has no solutions.
Jul
27
revised Obtain a contradiction
added something
Jul
21
comment find valuations
These Articles A, B, C and D may be of some use to you.
Jul
21
comment What is the sum of sum of digits of $4444^{4444^{4444}}$?
Have you seen this ? I think one can use the same thread of idea and extend it recursively to a higher notion.
Jul
19
comment Multiple-choice question regarding $\lim\limits_{n \to \infty} \sum\limits_{k = 1}^n \left| e^{2\pi ik/n} − e^{2\pi i(k−1)/n} \right|$
@Ranabir : See the difference between [previous question ]math.stackexchange.com/questions/172305/…) and this one. I noticed a drastic improvement. Good.
Jul
18
comment What are possibilities to disprove the Collatz Conjecture?
Wont this be of some use for you ?
Jul
18
comment Find $\lim_{n \rightarrow \infty}\sqrt{n}(A_{n+1} − A_n)$ where $A_n = \frac{1}{n}(a_1 + a_2 + \cdots + a_n)$
Please don't feel depressed and discouraged with the down-votes. Always remember these words, " WHEN SOME BODY HURTS YOU, THINK THEM AS SAND PAPER, THEY MAY HURT YOU IN THE BEGINNING, BUT WILL MAKE YOU END UP SHINING " . Welcome to MATH.SE again, have a great future. My best wishes.
Jul
18
comment Find $\lim_{n \rightarrow \infty}\sqrt{n}(A_{n+1} − A_n)$ where $A_n = \frac{1}{n}(a_1 + a_2 + \cdots + a_n)$
Please post the question along with the effort you did. Ask your question precisely and then clearly state where you got an obstacle that is not letting you to proceed further. (6) You can also use the Chat rooms, and see if some user is free to assist you from elementary level, but I can't promise that you find such users. There may be , there may not be. (7) Try reposting your questions , slowly you get upvotes and slowly your position will improve, users start responding to you. Trust me, I was in a more worst state when I entered, there were many times where I got 9 down votes and closed
Jul
18
comment Find $\lim_{n \rightarrow \infty}\sqrt{n}(A_{n+1} − A_n)$ where $A_n = \frac{1}{n}(a_1 + a_2 + \cdots + a_n)$
(5) I remember the Kinley mineral water bottle caption, it says : " We give back more than we take " , that should be your attitude. You shouldn't solely depend upon users for help. You must understand that each user will be having his own work and they are doing a free service for us, sparing their valuable time. Users like @GerryMyerson , and others may have busy schedules, some work as the professors in the university and are packed between their schedules. They can't help you from the scratch. Please do work on it as far as possible, and if you are unable to figure it out .. Contd.
Jul
18
comment Find $\lim_{n \rightarrow \infty}\sqrt{n}(A_{n+1} − A_n)$ where $A_n = \frac{1}{n}(a_1 + a_2 + \cdots + a_n)$
Dear Ranbhir, I think you are new to this community, it takes some time for you to get adjusted with the rules of this community . Being a member of this forum, I take the privilege to explain you these things. (1). Please phrase your questions with proper wording and REQUEST the users for the help. (2) Adding a simple THANK YOU, at the end will make your question appear interesting. (3) Please remove the habit of posting it as a homework assignment, People won't help you then. (4) Use the tag , <<Home Work >> if you want to hear hints.. Contd.