Iyengar
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 Aug 24 accepted How does a Class group measure the failure of Unique factorization? Aug 24 comment Is analytic capacity continuous from below? @timur : Thanks a lot sir. But everyone are not like you, people are narrow minded. Sometimes, due to people like you, I will realize that not everyone are brusque, there are quite a few who are ethical . Aug 22 revised Number to the exponent divided by exponent value added something Aug 22 suggested approved edit on Number to the exponent divided by exponent value Aug 20 comment Popular math books with depth Thank you FYI . Aug 20 comment Popular math books with depth Thank you FYI . Aug 16 comment If $a^2$ divides $b^2$, then $a$ divides $b$ +1. Really very simple proof, that makes no appeal to the Funda-Theorem of Arithmetic. Aug 13 comment Apollonius' circle My dear, its an assumption ( I think so, may be or may not be, the other MO users will step within a few time and help you in detailed manner ) . First you need to assume that they intersect at some point and then proceed further. In order to prove something, you need to assume something. BTW, its good that you mention the theorem name and link if possible. Aug 13 comment A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$ @J.M. : Yes sir. But tricky for me, silly for you ( learned people ) , is the meaning I wanted to express. Aug 13 comment A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$ It was really useful. I never thought it that way. Your explanation was clear and clean. It reflects your experience and grip in mathematics. Thank you again. Aug 13 comment A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$ Thank you, it was nice .+1. Aug 13 accepted A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$ Aug 13 comment A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$ It was really good one. +1 Aug 13 comment A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$ Thank you for your information. +1. Aug 13 comment A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$ Thank you. It was useful and good. +1. Aug 13 comment A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$ @anon : Thank you, I always have trouble with homophones. Aug 13 revised A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$ added something Aug 13 comment A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$ @RahulNarain : Thank you for your edit. Aug 13 comment On Albanese varieties @MakotoKato : Yes sir, it happened to me many times. Many people here are filled with grudges and I think you too know it and experienced it . But Thank you for your response. We never care about the reputation, and we should make it explicit. Either they must change or we must. I think the latter is better. Aug 13 asked A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$