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Aug
24
accepted How does a Class group measure the failure of Unique factorization?
Aug
24
comment Is analytic capacity continuous from below?
@timur : Thanks a lot sir. But everyone are not like you, people are narrow minded. Sometimes, due to people like you, I will realize that not everyone are brusque, there are quite a few who are ethical .
Aug
22
revised Number to the exponent divided by exponent value
added something
Aug
22
suggested approved edit on Number to the exponent divided by exponent value
Aug
20
comment Popular math books with depth
Thank you FYI .
Aug
20
comment Popular math books with depth
Thank you FYI .
Aug
16
comment If $a^2$ divides $b^2$, then $a$ divides $b$
+1. Really very simple proof, that makes no appeal to the Funda-Theorem of Arithmetic.
Aug
13
comment Apollonius' circle
My dear, its an assumption ( I think so, may be or may not be, the other MO users will step within a few time and help you in detailed manner ) . First you need to assume that they intersect at some point and then proceed further. In order to prove something, you need to assume something. BTW, its good that you mention the theorem name and link if possible.
Aug
13
comment A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$
@J.M. : Yes sir. But tricky for me, silly for you ( learned people ) , is the meaning I wanted to express.
Aug
13
comment A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$
It was really useful. I never thought it that way. Your explanation was clear and clean. It reflects your experience and grip in mathematics. Thank you again.
Aug
13
comment A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$
Thank you, it was nice .+1.
Aug
13
accepted A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$
Aug
13
comment A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$
It was really good one. +1
Aug
13
comment A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$
Thank you for your information. +1.
Aug
13
comment A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$
Thank you. It was useful and good. +1.
Aug
13
comment A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$
@anon : Thank you, I always have trouble with homophones.
Aug
13
revised A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$
added something
Aug
13
comment A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$
@RahulNarain : Thank you for your edit.
Aug
13
comment On Albanese varieties
@MakotoKato : Yes sir, it happened to me many times. Many people here are filled with grudges and I think you too know it and experienced it . But Thank you for your response. We never care about the reputation, and we should make it explicit. Either they must change or we must. I think the latter is better.
Aug
13
asked A tricky but silly doubt regarding the solutions of $x^2/(y-1)^2=1$