Davide Giraudo

56,349 reputation

54399

bio	website	univ-rouen.fr/LMRS/Persopage/…
	location	Rouen, France
	age	23
visits	member for	2 years, 1 month
	seen	just now
stats	profile views	5,691

I'm a Ph.D. student, working on limit theorems of probability theory.

My activity on math.stackexchange consists in:

trying to answer questions which didn't receive answers;
upvote/downvote questions/answers;
edits, retags of questions;
review tasks;
flag obsolete comments, answers which should be comments.

When I edit a post, I suggest the owner to check whether I didn't change the meaning.

	56,349 reputation	bio	website	univ-rouen.fr/LMRS/Persopage/…	visits	member for	2 years, 1 month
54399 badges		location	Rouen, France		seen	just now

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10,850 Actions

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3h	reviewed	No Action Needed Suitable change of measure with importance sampling
3h	reviewed	No Action Needed Question regarding Iteratively reweighted least squares?
3h	revised	Hilbert space proof edited tags
3h	reviewed	Leave Open Prove product of uniformly convergent sequences of functions is the product of the limiting functions
4h	reviewed	Approve suggested edit on Find an equation of the tangent line to a graph
4h	reviewed	Close Absolute summable sequence in normed space
5h	answered	Combining convergence in probability and the means of the positive sequence of r.v. implies convergence in L 1
5h	answered	Deducing a result about entire functions
7h	reviewed	Reviewed How is “n+n/2+n/4…1” equal to “2n-1” using the formula for geometric series?
7h	reviewed	Close positive semidefinite, positive definite?
7h	comment	Proving that $P\left(\bigcup_{j=1}^n E_j^{(n)}\right)\sim\sum_{j=1}^n P(E_j^{(n)})$ for independent events $E_j^{(n)}$ It's not what I said (I said that $\frac{\sum \mu(E_j)^2}{\sum\mu(E_j)}\leq \mu(\bigcup E_j)$.
1d	answered	Fourier analysis questions
1d	reviewed	Looks Good Mathematical Induction Check, $n! \leq n^n/2^n $
1d	answered	Tails of family of integrable functions
1d	comment	Proving that $P\left(\bigcup_{j=1}^n E_j^{(n)}\right)\sim\sum_{j=1}^n P(E_j^{(n)})$ for independent events $E_j^{(n)}$ Once you divide by this sum, we get something which converges to $0$ by assumption.
1d	reviewed	Close Weibull distribution - is it “heavy tailed” with three parameters? (prooving power law)
2d	answered	Proving that $P\left(\bigcup_{j=1}^n E_j^{(n)}\right)\sim\sum_{j=1}^n P(E_j^{(n)})$ for independent events $E_j^{(n)}$
May 22	answered	If $E(\|X+Y\|^p)<\infty$, then $E(\|X^p\|)<\infty$ and $E(\|Y^p\|)<\infty$.
May 21	revised	*Absolute value of an element in a C-algebra** edited tags
May 21	revised	$\mathcal{A}\perp_\mathcal{G}\mathcal{B}\wedge\mathcal{H}\subseteq\mathcal{G}\implies\mathcal{A}\perp_\mathcal{H}\mathcal{B}$? added 26 characters in body