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Oct
15
comment How to show holomorphic de Rham complex is exact?
In general, if you consider a triangulated manifold and look at the cdga of power series polynomial differential forms, how does the cohomology of this cochain complex compare to the cohomology of the (non power series) polynomial differential forms?
Jul
11
awarded  Popular Question
Apr
9
awarded  Yearling
Sep
19
revised exact differential n-forms
deleted 73 characters in body
Jul
2
awarded  Curious
Oct
23
revised Endomorphisms preserving bilinear form
deleted 58 characters in body
Oct
22
revised Endomorphisms preserving bilinear form
added 19 characters in body
Oct
22
comment Endomorphisms preserving bilinear form
Of course we can identify $End(V)$ with $V \otimes V^*$ which is isomorphic via $B$ to $V^* \otimes V^*$. Then the claim is that $L_B(V)$ inside $End(V)$ corresponds to $S^2(V^*)$.
Oct
22
comment Endomorphisms preserving bilinear form
How are you using the bilinear form $B$ or the corresponding element of $T^2(V^*)$ in the definition of $\alpha$? Also why are you writing an element of $V$ as a pair?
Oct
22
revised Endomorphisms preserving bilinear form
deleted 7 characters in body
Oct
22
asked Endomorphisms preserving bilinear form
Aug
7
awarded  Yearling
Jun
7
comment Sheafification of singular cochains
I just found a proof here www3.nd.edu/~lnicolae/sheaves_coh.pdf thank you!
Jun
7
accepted Sheafification of singular cochains
Jun
7
revised Sheafification of singular cochains
added 12 characters in body; deleted 1 characters in body; added 1 characters in body
Jun
7
asked Sheafification of singular cochains
Mar
8
asked Induced de Rham map is a ring map
Feb
19
accepted long exact sequence in $K$-theory
Feb
19
asked long exact sequence in $K$-theory
Nov
23
revised version of Bianchi identity
added 5 characters in body