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 Apr 20 awarded Yearling Feb 7 accepted Is there a name for dividing a set into pieces, some of which may be empty? Feb 5 comment Is there a name for dividing a set into pieces, some of which may be empty? The system of abstract convexity I am interested in, usually it is called a closure system, has as axioms: The sets $\varnothing$ and $X$ are convex. If $\mathcal{C}$ is a collection of convex sets then so is $\cap \mathcal{C}$. The vector space example is an instance of the situation I am interested in. Feb 5 comment Is The *Mona Lisa* in the complement of the Mandelbrot set. Thank you. That seems like it will work. There will be a certain amount of tediousness to fill in the details. Feb 5 accepted Is The *Mona Lisa* in the complement of the Mandelbrot set. Feb 5 awarded Nice Question Feb 5 asked Is there a name for dividing a set into pieces, some of which may be empty? Feb 5 comment Is The *Mona Lisa* in the complement of the Mandelbrot set. Your answer is an idea for a proof. I think that something like that will work. Unfortunately thinking something will work is not the same as proving it works. The hard part is describing the judicious positioning. Apr 20 awarded Yearling Apr 19 comment Is The *Mona Lisa* in the complement of the Mandelbrot set. If you look at the first picture at this link: artyfactory.com/art_appreciation/portraits/chuck_close.html you will see something like the type of picture I mean. The difference is that Chuck Close has doo-dads in the squares. I would use solid colors. Apr 10 comment Classifying Types of Paradoxes: Liar's Paradox, Et Alia @Memming That's what I wanted. Thanks. Apr 10 revised Classifying Types of Paradoxes: Liar's Paradox, Et Alia Changed the reference. Jan 15 answered How to justify “two-dimensional” induction Dec 10 awarded Caucus Oct 30 comment discuss convexity of the following set? mfl's suggestion to plot the region is a very good idea. Oct 9 reviewed Looks OK Conditional Integral of Square of Brownian Motion? Oct 6 answered Subset Relation: Is the subset relation a partial order? Oct 6 answered Prove that if X is a subset of Y then X intersect Z is a subset of Y intersect Z for all sets X, Y, Z. Sep 24 awarded Autobiographer Sep 8 comment The family of finite unions of half-open intervals forms a ring of sets It the nth term and the mth term do not intersect then you have written the empty set in a complicated way. You can delete all these different versions of writing the empty set.