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Aug
28
accepted Induced coaction on a vector space.
Aug
28
asked Induced coaction on a vector space.
Aug
26
answered Algebraic Peter-Weyl theorem in the case of $G=SL_2$.
Aug
26
comment How to compute an integral?
yes, I agree with you. Thank you very much.
Aug
26
comment How to compute an integral?
thank you very much. But in the formula it is $vol(\mathfrak{p}^{-k})$ not $vol((\mathfrak{p}^{-k})^{n-1})$.
Aug
26
accepted How to compute an integral?
Aug
26
asked How to compute an integral?
Aug
26
accepted What is the natural action of $U(\mathfrak{g})$ on $\mathbb{C}[G]$?
Aug
25
asked What is the natural action of $U(\mathfrak{g})$ on $\mathbb{C}[G]$?
Aug
17
accepted Unit commutes with $H$-action.
Aug
16
asked Unit commutes with $H$-action.
Aug
12
comment Do we have $\delta(ab)=\delta(a)\delta(b)$ implies $\Delta(cd)=\Delta(c)\Delta(d)$?
@darijgrinberg, I don't know whether $\delta(ab)=\delta(a)\delta(b)$ implies that $B$ is a bialgebra or not (that is $\Delta(cd)=\Delta(c)\Delta(d)$ for all $c,d \in B$).
Aug
12
comment Do we have $\delta(ab)=\delta(a)\delta(b)$ implies $\Delta(cd)=\Delta(c)\Delta(d)$?
@darijgrinberg, thank you very much. Yes, $A$ is a $B$-comodule algebra. I have edited the post. But we do not assume that $A, B$ are bialgebras in the beginning.
Aug
12
revised Do we have $\delta(ab)=\delta(a)\delta(b)$ implies $\Delta(cd)=\Delta(c)\Delta(d)$?
added 169 characters in body
Aug
12
revised Two questions about Schubert calculus and Schur functions.
added 2 characters in body
Aug
12
comment Do we have $\delta(ab)=\delta(a)\delta(b)$ implies $\Delta(cd)=\Delta(c)\Delta(d)$?
@Aaron, thank you very much. Yes, we only need the condition that $A$ is a comodule algebra.
Aug
12
comment Do we have $\delta(ab)=\delta(a)\delta(b)$ implies $\Delta(cd)=\Delta(c)\Delta(d)$?
@NajibIdrissi, thank you very much. I added that assume that $A, B$ are also algebras in the last line of the post.
Aug
12
revised Do we have $\delta(ab)=\delta(a)\delta(b)$ implies $\Delta(cd)=\Delta(c)\Delta(d)$?
added 47 characters in body
Aug
12
revised Do we have $\delta(ab)=\delta(a)\delta(b)$ implies $\Delta(cd)=\Delta(c)\Delta(d)$?
added 1 character in body
Aug
12
asked Do we have $\delta(ab)=\delta(a)\delta(b)$ implies $\Delta(cd)=\Delta(c)\Delta(d)$?