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Nov
9
answered Create list of {x,f(x)} pairs
Nov
9
asked Create list of {x,f(x)} pairs
Nov
7
comment A function of two functions that loses dependence on an argument
Craig: see edit, my case here is really an addition of sorts, so no undefined things pop up.
Nov
7
revised A function of two functions that loses dependence on an argument
multiplication->addition
Nov
7
asked A function of two functions that loses dependence on an argument
May
26
accepted Mathematica VectorPlot with Piecewise arguments
May
26
comment Mathematica VectorPlot with Piecewise arguments
Yeah, that should be removed. I changed the function to use HeavisideTheta instead of Piecewise, and now it works as it should. Don't really know where I went wrong...
May
26
asked Mathematica VectorPlot with Piecewise arguments
Apr
11
revised Choosing the branch of a logarithm
added assumption; added 3 characters in body
Apr
11
comment Choosing the branch of a logarithm
@joriki: yes I meant $-i\pi/3$, thanks for that. I thought a branch cut could be chosen arbitrarily, as long as it starts from a branch point (the origin in this case)?
Apr
11
awarded  Editor
Apr
11
revised Choosing the branch of a logarithm
added integrand; added 1 characters in body
Apr
11
awarded  Scholar
Apr
11
accepted Mathematica's “Solve” and filtering out the one real (non-complex) solution
Apr
11
accepted Analyticity of a function depending on $z$ and $\bar{z}$
Apr
11
asked Choosing the branch of a logarithm
Mar
25
awarded  Quorum
Mar
15
comment Mathematica's “Solve” and filtering out the one real (non-complex) solution
Same result, Mathematica seems unaware that $(-1)^{1/5}$ is a complex number... Although Im[(-1)^(1/5)] seems all right...
Mar
15
asked Mathematica's “Solve” and filtering out the one real (non-complex) solution
Mar
8
comment Analyticity of a function depending on $z$ and $\bar{z}$
@Fabian: All right, gotcha :)