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 Nov 9 answered Create list of {x,f(x)} pairs Nov 9 asked Create list of {x,f(x)} pairs Nov 7 comment A function of two functions that loses dependence on an argument Craig: see edit, my case here is really an addition of sorts, so no undefined things pop up. Nov 7 revised A function of two functions that loses dependence on an argument multiplication->addition Nov 7 asked A function of two functions that loses dependence on an argument May 26 accepted Mathematica VectorPlot with Piecewise arguments May 26 comment Mathematica VectorPlot with Piecewise arguments Yeah, that should be removed. I changed the function to use HeavisideTheta instead of Piecewise, and now it works as it should. Don't really know where I went wrong... May 26 asked Mathematica VectorPlot with Piecewise arguments Apr 11 revised Choosing the branch of a logarithm added assumption; added 3 characters in body Apr 11 comment Choosing the branch of a logarithm @joriki: yes I meant $-i\pi/3$, thanks for that. I thought a branch cut could be chosen arbitrarily, as long as it starts from a branch point (the origin in this case)? Apr 11 awarded Editor Apr 11 revised Choosing the branch of a logarithm added integrand; added 1 characters in body Apr 11 awarded Scholar Apr 11 accepted Mathematica's “Solve” and filtering out the one real (non-complex) solution Apr 11 accepted Analyticity of a function depending on $z$ and $\bar{z}$ Apr 11 asked Choosing the branch of a logarithm Mar 25 awarded Quorum Mar 15 comment Mathematica's “Solve” and filtering out the one real (non-complex) solution Same result, Mathematica seems unaware that $(-1)^{1/5}$ is a complex number... Although Im[(-1)^(1/5)] seems all right... Mar 15 asked Mathematica's “Solve” and filtering out the one real (non-complex) solution Mar 8 comment Analyticity of a function depending on $z$ and $\bar{z}$ @Fabian: All right, gotcha :)