322 reputation
215
bio website http://--
location Belgium
age 24
visits member for 3 years, 11 months
seen Jul 16 at 9:46
Physics Student at the University of Antwerp

Jul
30
asked What's the meaning of the unit bivector i?
May
17
awarded  Popular Question
Nov
21
accepted Create list of {x,f(x)} pairs
Nov
21
accepted A function of two functions that loses dependence on an argument
Nov
9
awarded  Commentator
Nov
9
comment Using Fit on functions that use matrix calculation
Mikael: well, it doesn't remove the problem unfortunately :( Maybe something else is wrong. I'll see to providing a simple reduction of what I have so people can see if they can find what's wrong.
Nov
9
comment Using Fit on functions that use matrix calculation
Mikael: does the function still work as a function then? The variables change color, and I'm worried what other implications could arise...
Nov
9
asked Using Fit on functions that use matrix calculation
Nov
9
comment Create list of {x,f(x)} pairs
Funny how the (IMHO) much worse pops up in comments under my answer :)
Nov
9
answered Create list of {x,f(x)} pairs
Nov
9
asked Create list of {x,f(x)} pairs
Nov
7
comment A function of two functions that loses dependence on an argument
Craig: see edit, my case here is really an addition of sorts, so no undefined things pop up.
Nov
7
revised A function of two functions that loses dependence on an argument
multiplication->addition
Nov
7
asked A function of two functions that loses dependence on an argument
May
26
accepted Mathematica VectorPlot with Piecewise arguments
May
26
comment Mathematica VectorPlot with Piecewise arguments
Yeah, that should be removed. I changed the function to use HeavisideTheta instead of Piecewise, and now it works as it should. Don't really know where I went wrong...
May
26
asked Mathematica VectorPlot with Piecewise arguments
Apr
11
revised Choosing the branch of a logarithm
added assumption; added 3 characters in body
Apr
11
comment Choosing the branch of a logarithm
@joriki: yes I meant $-i\pi/3$, thanks for that. I thought a branch cut could be chosen arbitrarily, as long as it starts from a branch point (the origin in this case)?
Apr
11
awarded  Editor