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seen Dec 16 '13 at 16:56

Oct
18
comment Threshold of connectivity in a random graph
So how do you arrive at $(1-p) \leqslant \mathrm{e}^{-p}$? Or is it another inequality?
Oct
18
comment Threshold of connectivity in a random graph
Thanks very much for your reply once again! For the second equation I understand how it works (which confirmed my understanding) but still I do not see the connection between the first one, the line that concludes the formal proof, and the inequalities I've provided that should facilitate arriving at the proof. Could you, please, elaborate on it?
Oct
15
comment Threshold of connectivity in a random graph
Well, as I stated in the post, I cannot arrive at the last line of the proof. I've reported my derivations which lead me nowhere w.r.t. the proof, so the question is basically, how given the two inequalities (before my own intervention after the $\therefore$ symbol) the line of the proof can be obtained?
Apr
30
comment Combination of splitting elements into pairs
@user6312, thank you!
Apr
29
comment Combination of splitting elements into pairs
I see. Thanks very much!
Apr
28
comment Problem about number of vertices of a graph
@Jim Conant and @lhf: Thank you!
Apr
28
comment Problem about number of vertices of a graph
Thanks very much for the explanation!
Apr
10
comment Permutation/Combination of x,y and z moves
12 was a typo. Fixed now. Excuse me, I don't understand what you mean with your second question. Could you, please, be more specific?
Apr
9
comment Permutation/Combination of x,y and z moves
Thanks! Indeed it is a very good alternative.
Apr
9
comment Permutation/Combination of x,y and z moves
Now I get it. I tried to approach it analogically starting with y, then z, and leaving x for the end. I got the same answer $\binom{13}{4} \binom{9}{7} = 25740$. Thank you!