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 14h awarded Nice Answer Apr3 awarded Nice Answer Apr3 awarded Popular Question Mar20 awarded Popular Question Jan8 awarded Necromancer Dec15 awarded Caucus Sep30 awarded Explainer Sep24 awarded Autobiographer Sep3 comment How many numbers are less than million such that their digits sum is $\le 19$? @jj172 I think that this does answer one of the two questions that were asked. Actually to me it is a better answer than just "the coefficient of $x^{19}$ in the following expression". Don't feel discouraged because someone downvoted your answer, there are other people like me, who value computational answers like this one just as much as a more theoretical one. Aug14 comment Clarification on The Trichotomy Law I suppose you mean [trichotomy law](en.wikipedia.org/wiki/Trichotomy_(mathematics). Aug7 awarded Yearling Jul12 awarded Good Question Jul2 awarded Curious Jul2 awarded Inquisitive Jun22 awarded Nice Answer Jun17 comment How to show that $\int \limits_{-\infty}^{\infty} (t^2+1)^{-s} dt = \pi^{1/2} \frac{ \Gamma(s-1/2)}{\Gamma(s)}$ Thank you Lucian, it worked perfectly. Jun17 accepted How to show that $\int \limits_{-\infty}^{\infty} (t^2+1)^{-s} dt = \pi^{1/2} \frac{ \Gamma(s-1/2)}{\Gamma(s)}$ Jun17 asked How to show that $\int \limits_{-\infty}^{\infty} (t^2+1)^{-s} dt = \pi^{1/2} \frac{ \Gamma(s-1/2)}{\Gamma(s)}$ May28 comment Given $f:(0,\infty ) \to \mathbb{R}$ Can we say that $\lim_{x\to \infty} f(x)$ exists? I would guess that by saying does "finite $\implies$ $f$ is bounded"?, the OP means to ask if it is the case that having a finite limit when $x \rightarrow \infty$ implies that $f$ is bounded on $(0,\infty)$. But this is just a guess. Apr23 answered A question of algebraic geometry applied to field theory