Matheus Silva
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 Mar10 asked Prove by induction that $\frac{x^{n}-1}{x-1}$ is an integer Dec3 awarded Curious Nov5 awarded Popular Question Jul17 accepted Definition of “quotient set” Jun19 comment Normal distribution of t @Ragnar the total population(10000) the average($\mu$) is 50.03385, and the average from the sampling that i made(i took 10 from 10000) is 70.32416. yes, its correct, i checked using excel. Jun19 asked Normal distribution of t Jun19 suggested rejected edit on T student distribution Jun18 comment (correction)Sampling distribution homework i dont know if i found correctly, based on bernoulli distribution i find the variance = 0,21 and the mean = 0,3, on binomial distribution looking on the histogram and calculatin the mean = 1,5 and variance = 1,05. Which one is correctly? Jun18 comment (correction)Sampling distribution homework in the question is MSE($\bar{X},\mu$), so, MSE = E($\bar{X} - \mu)^2)$ Jun18 comment (correction)Sampling distribution homework and to know the squared mean error? Jun18 accepted (correction)Sampling distribution homework Jun18 revised (correction)Sampling distribution homework edited title Jun18 asked (correction)Sampling distribution homework Dec7 comment identity and inverse elements from a group So, i was thiking better, the inverse is 1/(a,b) = (1/a, 1/b). (a,b)*(1/a, 1/b) = 1 -> a*1/a = 1 | b*1/b = 1 -> (1,1). (a,b)*(j,k) = (1,1) where (j,k) is any inverse, so its the only way to achieve (1,1). Dec7 comment identity and inverse elements from a group i was thinking better, why i can just consider (0,0) as the inverse? Dec7 comment identity and inverse elements from a group so, i understand that (C,D) is (1,1) correct? is the only way to achieve (a,b). ok, and considering (0,0) as inverse, multipling by (a,b) (or whatever) it will not exist(will be 0,0) correct? so, dont have an inverse. Dec7 comment identity and inverse elements from a group @JinyongGo '-', so, how can i show there is not an inverse element? and its not a group Dec7 comment identity and inverse elements from a group @JinyongGo how it should be? and, the logic is correct? Dec7 comment identity and inverse elements from a group i wrote the entire question. Dec7 revised identity and inverse elements from a group added 125 characters in body