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Mar
10
asked Prove by induction that $\frac{x^{n}-1}{x-1}$ is an integer
Dec
3
awarded  Curious
Nov
5
awarded  Popular Question
Jul
17
accepted Definition of “quotient set”
Jun
19
comment Normal distribution of t
@Ragnar the total population(10000) the average($\mu$) is 50.03385, and the average from the sampling that i made(i took 10 from 10000) is 70.32416. yes, its correct, i checked using excel.
Jun
19
asked Normal distribution of t
Jun
19
suggested rejected edit on T student distribution
Jun
18
comment (correction)Sampling distribution homework
i dont know if i found correctly, based on bernoulli distribution i find the variance = 0,21 and the mean = 0,3, on binomial distribution looking on the histogram and calculatin the mean = 1,5 and variance = 1,05. Which one is correctly?
Jun
18
comment (correction)Sampling distribution homework
in the question is MSE($\bar{X},\mu$), so, MSE = E($\bar{X} - \mu)^2)$
Jun
18
comment (correction)Sampling distribution homework
and to know the squared mean error?
Jun
18
accepted (correction)Sampling distribution homework
Jun
18
revised (correction)Sampling distribution homework
edited title
Jun
18
asked (correction)Sampling distribution homework
Dec
7
comment identity and inverse elements from a group
So, i was thiking better, the inverse is 1/(a,b) = (1/a, 1/b). (a,b)*(1/a, 1/b) = 1 -> a*1/a = 1 | b*1/b = 1 -> (1,1). (a,b)*(j,k) = (1,1) where (j,k) is any inverse, so its the only way to achieve (1,1).
Dec
7
comment identity and inverse elements from a group
i was thinking better, why i can just consider (0,0) as the inverse?
Dec
7
comment identity and inverse elements from a group
so, i understand that (C,D) is (1,1) correct? is the only way to achieve (a,b). ok, and considering (0,0) as inverse, multipling by (a,b) (or whatever) it will not exist(will be 0,0) correct? so, dont have an inverse.
Dec
7
comment identity and inverse elements from a group
@JinyongGo '-', so, how can i show there is not an inverse element? and its not a group
Dec
7
comment identity and inverse elements from a group
@JinyongGo how it should be? and, the logic is correct?
Dec
7
comment identity and inverse elements from a group
i wrote the entire question.
Dec
7
revised identity and inverse elements from a group
added 125 characters in body