Praphulla Koushik
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 2d accepted computing Lefschetz number 2d comment computing Lefschetz number This is much more than what i have asked... I have got some idea but i am not used to some of the ideas that you have informed... But it is really motivating how this is related to fundamental theorem of algebra.... Thanks.. I think this answers my question Apr24 comment computing Lefschetz number Oh no... I got it... I don't know how i missed that simple point... @John Apr24 comment computing Lefschetz number @John : How is that $1$.. How do i even proceed for that.. Can you give some hint.... Apr24 comment computing Lefschetz number what about some simple maps such as nullhomotopic maps? Is there any way @John Apr24 asked computing Lefschetz number Apr24 accepted simply connected covering of a path connected space (II) Apr24 comment simply connected covering of a path connected space (II) Got it... Thank you :) Apr23 comment simply connected covering of a path connected space (II) I thank you for your reply but I am afraid I am not fully ready to read a paper at this time as I am just learning the subject... I will definitely come to this once I am ready.. Thank you Apr23 comment simply connected covering of a path connected space (II) Oh.. Ok ok.. So we actually have a loop but then...what next.. As that lift is a loop it has to be nullhomotopic.. Then compose with p again and say that this is nullhomotopic in A... Apr23 comment simply connected covering of a path connected space (II) Let $\omega$ be a loop in $A$ null as a loop in $X$... We have $H:I\times I \rightarrow X$ such that $H(t,0)=\omega(t)$ and $H(t,1)=\omega(0)$. We then have a lift $\tilde H : I\times I \rightarrow \tilde X$ such that $p\circ \tilde H= H$... The lift $\tilde\omega$ may not be a loop in $\tilde X$.. we get a path in $p^{-1}(A)$.. As $a=\tilde\omega(0)$ may not be same as $b=\tilde\omega(1)$ we can get a path $\tau$ from $a$ to $b$ then $\tau*\tau^{-1}$ is a loop in $p^{-1}(A)$ and as $p^{-1}(A)$ is simply connected we have $\tau*\tau^{-1}\approx c$..I do not know how to proceed next Apr23 comment simply connected covering of a path connected space (II) I am sorry, I mean to say it is simply connected... Apr23 revised simply connected covering of a path connected space (II) added 2 characters in body Apr23 comment Why every algebra on finite set is a topology how good is to change the question when some one already answered it... Apr23 asked simply connected covering of a path connected space (II) Apr21 reviewed Approve Finding the Laurent series given the poles and residues Apr21 comment $f(x) =\ln(2x^2 + 1)$ is continuous on $\mathbb{R}$ Did you get the answer?? Apr21 comment Boundedness Theorem for continuous functions on intervals Is $f(x)=\frac{1}{x}$ continuous on $(0,1)$.. Is it bounded?? Apr20 comment Section of a covering projection from a connected space @NajibIdrissi : Thanks Apr20 comment Im(AB) $\subset$ Im A you are welcome