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 Jun3 comment Factoring in the derivative of a rational function Thank you for your references Jun3 comment Factoring in the derivative of a rational function Thank you very much for your examples in continuing it. Jun3 comment Factoring in the derivative of a rational function Ahhhh. So much time looking at it and I didn't realise this. I don't know about the factor theorem, something to look at. Thank you for your answer. Jun3 comment Finding Domain of a Function with a Fraction Inside a Square Root Thank you for your answer ! I didn't think about approaching it at once like here, but I don't get the part of finding the domain so quickly, maybe a trick? Sorry I'm unable to see the "middle path" of it! Jun3 comment Finding Domain of a Function with a Fraction Inside a Square Root Thank you very much. I didn't remember about this procedure but now makes all sense. Much appreciated Oct13 comment Comparing Powers of Different Bases Thanks once again for the explanation @ArturoMagidin Oct12 comment Comparing Powers of Different Bases @ArturoMagidin I know :-) But which one is bigger: $2^{2000}$ or $10^{800}$? I'd like to know about cases like this one. Edit: You should post this edit in your comment as answer. May12 comment Homework with logarithms Very clever! Well, following the idea $\log_{c}2 = 1$ (if I'm not mistaken), but unfortunately I've just checked the workbook answers (answers are provided, resolutions not) and it should be 4, not 11. Hmm, probably there is something wrong with the exercise. I'll search for my teacher tomorrow in school and ask him about this exercise. Thanks a lot you all, I'll post any news. cc @Isaac @GEdgar @Nana May12 comment Homework with logarithms A lot easierâ€¦ Thanks for pointing it out Nana. May12 comment Homework with logarithms @Isaac, thanks. I was also thinking that could be no apparent solution, but know @GEdgar and @Skatche proposals are clarifying some aspects. The source book is really vague. I'll check the answer â€” I guess there is an error with this exercise. May4 comment Simplifying a Trigonometric Expression Thank you Joe. I ended up marking the other answer as correct, as it shows the complete solution. I hope you understand! But your explanation was certainly helpful, it was the kind of answer I was waiting. I'm sure I'd continue and find the solution after reading it. Thanks again! Best wishes May4 comment Simplifying a Trigonometric Expression Well, thank you a lot Nicolas! What else can I say? Mar30 comment Is this a kind of Permutation? +1, thanks for your answer sir, and for providing the useful links. Mar30 comment Is this a kind of Permutation? Thanks a lot for your comprehensive answer. Math is such a beautiful thing! Tuples is a new term for me. Most of the others I started to remember from school, but it was really useful to read this here as my primary education was not in english, and I'm now having to relearn many terms. If I may answer the questions, the first for the $k$-permutation would be $\frac{n!}{(n-k)!}$, or something like that, right? The $n$-permutation is easy: $n!$. Now, I'm not quite sure if I can convince myself why there are no $n+1$-permutations. Does $n+1$ relates to the set, without sufficient elements?