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Feb
27
answered Newtonian Mechanics - Differential equation
Feb
27
answered Finding a differential equation from $y = (c_1+c_2x)e^x+c_3$
Feb
27
answered Finding inverse of matrix
Feb
27
revised Floor function inequality, for which x<y real is $\lfloor x \rfloor < \lfloor y \rfloor$?
edited tags
Feb
27
answered Show that $3x^2-4x+2$ is always greater than $0$.
Feb
27
comment Splitting of extenion in group theory
This is a good related question and these ones are well designed answers full of points.
Feb
27
revised Regarding the order of elements in a factor group
edited tags
Feb
26
comment Why Maple fails to judge $x < \tan(x)$ assuming $0<x<\pi/2$?
Ali jan aya ino tu Mapleprime.com matrah kardi? Age jawabi naymad unja ham ye try bokon. :-)
Feb
26
comment Derivative with a Square root in Denominator
Have a wonderful time my friend. I'll try to get back soon. One of my article is going to be published at Korean Mathematical Society. :-)
Feb
10
revised The graph of the function is $g(x)=x^3-2x^2+x+1$ and the tangent to the curve is at $x=2$?
added 85 characters in body
Feb
10
answered The graph of the function is $g(x)=x^3-2x^2+x+1$ and the tangent to the curve is at $x=2$?
Feb
10
answered General solution to the integral of 4/x
Feb
10
comment All points at which the surfaces $x^2+y^2+z^2-1=0$ and $x^2+y^2-z^2-2y=0$ are intersect orthogonally
@amWhy: Nice to see you again as the Sun rises up every morning. :-)
Feb
9
revised Area of a sphere bounded by a paraboloid
edited tags
Feb
9
answered How to get to a desired expression?
Feb
9
comment How to get to a desired expression?
I am confused be your first expression. :)
Feb
9
comment Is the function continuous at x=0?
In the denominator we have [1/x] in the function rules. :)
Feb
9
answered All points at which the surfaces $x^2+y^2+z^2-1=0$ and $x^2+y^2-z^2-2y=0$ are intersect orthogonally
Feb
9
comment Is the function continuous at x=0?
good to see that $x\in (0,1]\Longleftrightarrow \frac{1}{x}\in [1,+\infty)$
Feb
9
comment Is the function continuous at x=0?
Is cont. from the right, you mean?