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14h
comment Visualize $z+\frac{1}{z} \ge 2$
That's not true for $z<0$. Maybe you mean $z\in\mathbb R^+$. Anyway, for a geometrical interpretation, one can compare the graph of $y=1/x$ and $x+y=2$: wolframalpha.com/input/?i=plot%20y%3D1%2Fx%2C%20x%2By%3D2
1d
comment Ideal shape for underwater habitat
I'm not sure I understand your analogy. A drop of liquid typically does not change its volume -- do you mean its surface area? Also, if the external air pressure is uniform it does not influence the shape of an incompressible drop, because the work done against a uniform pressure field depends only on the change in volume.
1d
revised Is 'difference of two squares' in this limit proof acceptable?
easier to read exponents
2d
comment Sane solution for an ODE with physical interpretation
You can't avoid singularities, because any solution to $v'=v^2$ with $v$ initially positive goes to infinity in finite time. Your "physical process" is not physically realizable.
2d
comment Are closed simple curves with that property necessarily circles?
Consider any region with four-fold rotational symmetry, such as a square...
2d
comment Is 'difference of two squares' in this limit proof acceptable?
I'm afraid you can't plug in the "last element" of an infinite sequence like that. The moment you started talking about $a^{k/\infty}$ your proof was invalid.
2d
comment Origin of the term dual space?
Typically, the term dual is applied when the dual of the dual is the original object. Wikipedia has a host of examples.
2d
comment Explicit Bezier Curves: Lerping between curves same as lerping control points?
This is a consequence of the fact that $f$ is linear in $A$, $B$, and $C$, and similarly for $g$.
2d
comment Distribution formed by taking two random points on an open disc and graphing their midpoint
The probability density at any point $p$ is proportional to the area of the set of points $q$ such that both $q$ and its reflection about $p$ lie inside the disk. This is definitely higher in the middle than near the boundary.
May
22
comment Given two points, how to find a circle through them that's also tangent to the $x$-axis?
A Euclidean geometry construction: cut-the-knot.org/Curriculum/Geometry/GeoGebra/PPL.shtml
May
21
comment Does a fluid with $0$ divergence have $0$ density?
If $\mathrm d\rho/\mathrm dt=0$, it doesn't mean that $\rho=0$. It just means that $\rho$ is constant. (Everyone forgets the constant of integration, grumble grumble...)
May
21
comment Way to measure the similarity/difference of 2D point clouds
If the curves are noisy, that could still throw the arc length parametrizations out of sync (imagine one curve is noisier near the beginning and the other is noisier near the end, and you get the same situation as my first comment). Which is why I suggested the Hausdorff distance, which is independent of parametrization.
May
21
comment Way to measure the similarity/difference of 2D point clouds
This is halfway to a good idea. But if the first point set has a lot of points near the beginning of the curve and the second has lots of points near the end of the same curve, your metric will still give a large dissimilarity. What you should do, once you have a notion of the curves represented by each point set, is to measure the geometrical dissimilarity between the curves themselves, for example using the Hausdorff distance.
May
21
revised Total area for a natural nested set of convex polygons.
added 18 characters in body
May
21
revised Total area for a natural nested set of convex polygons.
deleted 15 characters in body
May
21
revised Total area for a natural nested set of convex polygons.
added 547 characters in body
May
21
comment Total area for a natural nested set of convex polygons.
Whoops, that's not quite true. When $n$ is large and odd, $P^*$ forms two simple polygons of area close to $A$, so $A^*\approx A$, or a single "doubly-wrapped" polygon whose central area is double-counted, and again $A^*\approx A$. I'll edit my answer.
May
21
revised Total area for a natural nested set of convex polygons.
added 50 characters in body
May
21
answered Total area for a natural nested set of convex polygons.
May
20
comment Why $ (A\vec{x})'A \vec{x} = \vec{0}$ implies that $A\vec{x} = \vec{0}$
You still have $A^TAx=x^TA^TAx$, which is also incorrect.