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Mar
17
answered problem or doubt regarding visualizing angles of spherical triangle
Mar
17
answered Can SAT instances be solved using cellular automata?
Mar
16
awarded  numerical-methods
Mar
16
comment The average denominator of the continued fraction expansion of $\pi$.
I'm suspicious of how you obtained your plot. To get the millionth term in the continued fraction, you'll need an awfully good approximation for $\pi$.
Mar
16
comment Integral of $f^2$ exists, but integral of $f$ doesn't.
"Exists" in what sense? Are you talking about Riemann integrals, improper Riemann integrals, or Lebesgue integrals?
Mar
16
answered How do I prove $\frac{n}{\sqrt[n]{n!}}$ is either monotonic and bounded, or Cauchy?
Mar
15
comment Runge-Kutta 4 - solving system of 6 differential equations (BVP)
Since you mentioned Maple, you might note that Maple's dsolve includes solvers for boundary value problems. Unless there's some particular reason you have to use RK4, you're probably better off giving the problem to Maple as a boundary value problem.
Mar
15
revised Approximate probability that $20$ out of $100$ will last less than time $(x)$
added 289 characters in body
Mar
15
answered Approximate probability that $20$ out of $100$ will last less than time $(x)$
Mar
15
awarded  Nice Answer
Mar
15
answered $(X_n)$ an irreducible transient Markov chain. Is $f(x) = \mathbb{P}(X_n = x_0 \text{ for some } n > 0 | X_0=x)$ constant?
Mar
15
revised decimal expansion and square roots
added 316 characters in body
Mar
15
answered decimal expansion and square roots
Mar
15
comment Converting Prime Numbers from Base $10$ to Base $4$
See OEIS sequence A065722, oeis.org/A065722
Mar
15
awarded  Nice Answer
Mar
15
answered Enlightening proof that the algebraic numbers form a field
Mar
15
answered Do people ever study non-commutative fields?
Mar
15
comment Analytic solution to explicit midpoint rule applied to an ODE
The differential equation is supposed to be $y' = f(t,y)$, right?
Mar
15
answered Analytic solution to explicit midpoint rule applied to an ODE
Mar
15
comment Solutions to two Bézout equations solve a third one
Now you're jumping to conclusions with $d=-a$ and $c=-b$: should be $d=q-a$ and $c=p-b$.