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Learning from scratch.


Sep
14
comment Finding limit of $\lim\limits_{h\to 0} \frac1{h}\left(\frac1{\sqrt{x+h-2}}-\frac1{\sqrt{x-2}}\right)$
@Srivatsan Thanks. I edited my answer.
Sep
13
revised Finding limit of $\lim\limits_{h\to 0} \frac1{h}\left(\frac1{\sqrt{x+h-2}}-\frac1{\sqrt{x-2}}\right)$
edited body
Sep
13
revised Finding limit of $\lim\limits_{h\to 0} \frac1{h}\left(\frac1{\sqrt{x+h-2}}-\frac1{\sqrt{x-2}}\right)$
deleted 18 characters in body
Sep
13
revised Finding limit of $\lim\limits_{h\to 0} \frac1{h}\left(\frac1{\sqrt{x+h-2}}-\frac1{\sqrt{x-2}}\right)$
added 115 characters in body
Sep
13
answered Finding limit of $\lim\limits_{h\to 0} \frac1{h}\left(\frac1{\sqrt{x+h-2}}-\frac1{\sqrt{x-2}}\right)$
Sep
12
accepted Cycle notation question
Sep
12
accepted Why is closure omitted in some group definitions?
Sep
11
comment Why is closure omitted in some group definitions?
Yes. Yours and Arturo's assessment is correct. The existence of the binary operation was made explicit in the definitions which did not require closure. I did not notice this as I thought that of a binary operation as $*:A\times A \rightarrow \mbox{Anything}$, or didn't think of it at all.
Sep
11
asked Why is closure omitted in some group definitions?
Sep
11
comment Cycle notation question
Ahh. Thanks. I feel silly now.
Sep
11
asked Cycle notation question
Sep
10
revised Proof that a bijection has unique two-sided inverse
edited title
Sep
10
comment Proof that a bijection has unique two-sided inverse
@robjohn I have edited the question to include the motivation
Sep
10
revised Proof that a bijection has unique two-sided inverse
added 115 characters in body
Sep
10
asked Proof that a bijection has unique two-sided inverse
Sep
8
answered What is your favorite application of the Pigeonhole Principle?
Sep
6
awarded  Electorate
Sep
5
answered how many times will a function print to the console?
Sep
5
revised Basic kinematics question
added 208 characters in body
Sep
5
answered Basic kinematics question