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Dec
17
revised $f\geq 0$, continuous and $\int_a^b f=0$ implies $f=0$ everywhere on $[a,b]$
improving title
Dec
16
answered Does $f(x)$ is continuous and $f = 0$ a.e. imply $f=0$ everywhere?
Dec
15
revised $f\geq 0$, continuous and $\int_a^b f=0$ implies $f=0$ everywhere on $[a,b]$
typo
Dec
15
revised Inverse matrix norm under simple conditions
formatting
Dec
15
comment Find the upper and lower limits of $xf(x)$, as $x\rightarrow \infty$
In yor solution, how do you get the first inequality, notice that in $f$ the integral is respect to $t$, no $x$
Dec
15
comment Find the upper and lower limits of $xf(x)$, as $x\rightarrow \infty$
What do you mean by "Of course I calculated that function"
Dec
15
comment Proving that if $g(x)$ is injective, and $g(f(x))$ is injective, then $f(x)$ is injective
@pie you can accept this answer.
Dec
15
comment Inverse function of a polynomial
How is this different from the original question?
Dec
14
comment Iterated Integrals - “Counterexample” to Fubini's Theorem
You can answer your own question. You can even accept your answer =)
Dec
14
comment Book recomendations for Smooth manifolds.
Springer link. Perhaps useful to someone
Dec
14
revised Old graduate analysis qualifying exam question
improving formatting
Dec
10
comment How to solve recurrence equation $f(n) = f(n-5) + f(n-10)$?
$x^{10}-x^{5}-1=0$
Dec
10
accepted Possible mistake in Boothby's Manifolds book
Dec
10
revised Possible mistake in Boothby's Manifolds book
added 261 characters in body
Dec
10
comment Possible mistake in Boothby's Manifolds book
You are right. I was wrong. The thing is that one page before he calls left coset to something that is right coset in a context where there is no reason for they to be the same thing. That was what confused me.
Dec
10
comment Possible mistake in Boothby's Manifolds book
I did it with that relation because it is as he define in a previous pages. With your equivalence relation the class of $g_2$ is $[g_2]=g_2G_{x_0}$ which seems like a right coset.
Dec
9
revised Possible mistake in Boothby's Manifolds book
added 4 characters in body
Dec
9
asked Possible mistake in Boothby's Manifolds book
Dec
8
comment If $P \leq G$, $Q\leq G$, are $P\cap Q$ and $P\cup Q$ subgroups of $G$?
Good answer. For the sake of completeness, if $P\cup Q$ is a subgroup what does it implies?
Dec
5
revised A problem concerning the Measurable function
added 8 characters in body