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 Jan12 answered Vector subspaces of $\mathbb{R}[x]_n$ result Jan9 awarded Announcer Jan4 comment If every vector is an eigenvector, the operator must be a scalar multiple of the identity operator? Related Dec29 comment Prove $A=\{x\in \mathbb{R}|f(x)=x\}$ is closed subset of $\mathbb{R}$ Sequentially closedness. Dec20 awarded Constituent Dec12 comment On the problem of polynomial bijection from $\mathbb Q\times\mathbb Q$ to $\mathbb Q$ What this seems like is material worth a blogpost. Dec11 revised $\lim_{p\to \infty}\Vert f\Vert_{p}=\Vert f\Vert_{\infty}$? added 5 characters in body; edited title Dec11 comment Relevant Dec10 comment If $\sigma$ is a cycle of length $r$, then it has order $r$? @darijgrinberg Would you like to put your comment as an answer. I'll upvote it. Dec10 comment @PedroTamaroff I don't chat as often as I used to, the few times I've been there recently, I found some things that made me form some opinion. For what is worth, I remember I used to appreciate being in chat when you were around. More, when the talk was about math. Just to make clear that I'm not trying to screw you on this elections. Dec9 comment The good thing about being active in chat is that many people gets to know you. This kind of behavior seems pretty much in opposite direction to lead by example and being patient and fair, not to talk about respect. Dec8 awarded Caucus Dec6 awarded Nice Question Dec6 revised Prove that $f$ is constant edited title Nov28 revised How do I find the characteristic polynomial and eigenvalues? deleted 4 characters in body Nov26 revised Verifying an equivalence relation Formatting Nov26 revised Verifying an equivalence relation added 7 characters in body Nov16 comment what is the set $\mathbb R[X]$ defined as? Nice answer. Multiplication can also be defined the same way for the formal power series, so multiplication of polynomials can be realized as the restriction of that one. Nov15 answered Eigenvalues of operator $p(T)$ in terms of the eigenvalues of $T$, where $p$ is a polynomial Nov13 revised $A\in M_2(\mathbb C)$ and $A$ is nilpotent then $A^2=0$.How to prove this? added 39 characters in body