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comment Deleting $n$ points from a connected space
@NielsDiepeveen If we remove one point in the center, the result is connected.
May
17
comment Deleting $n$ points from a connected space
@GrumpyParsnip It suffices to take $n=1$.
May
17
comment Deleting $n$ points from a connected space
If we remove the "each of which is homemorphic to $X$" condition, the long line is such a space.
May
16
answered Why can't you add apples and oranges, but you can multiply and divide them?
May
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comment Area of a part of a square
@Maroon We can do a little better than that, with $L^2\in (18,26)$. It seems to me that $A$ should be unique, since choosing the central point provides two degrees of freedom while we are given three values, but I can't prove it off the top of my head.