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bio website jamesrohal.com
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visits member for 3 years, 9 months
seen Dec 12 at 1:15

Jul
17
asked Zariski Closed Set Notation
May
31
awarded  Editor
May
31
revised Why is this function bounded and Lipschitz?
Removed incorrect statement.
May
31
awarded  Student
May
31
comment Why is this function bounded and Lipschitz?
Not necessarily, but it turns out (almost always) that $g$ has finitely many critical points on $f \neq 0$. Plus I know each connected component of $f \neq 0$ has at least one local max.
May
31
comment Why is this function bounded and Lipschitz?
Intuitively all of these seem obvious. For example, $g$ should be bounded above by $\max g(c)$ where $c$ is a critical point of $g$. I feel like all of the proofs could be done by contradiction but I was looking for something more explicit (i.e., "this is the upper bound", or "this is the Lipschitz constant").
May
31
asked Why is this function bounded and Lipschitz?